Solved How to retrieve the name of an extracted Base64 file?

Yes it is the File metadata, sorry.
So, I've followed your advice, it works perfectly.

(Here, what I called PATH_BASE64 is nammed AEL_PATH_BASE64.)





Thank you again.

Hum, actually, it seems that it is not the correct behaviour.
It still works, but my files are extracted to the Stambia temp directory, and not where I want.

Here is the path of my 2 example files:




I guess there is something wrong about the visibily of the parameter, but I don't know what. I think I've followed what you advise me, but it seems that ${~/extractdir}$ doesn't compile.

Unfortunately, I have the same behaviour with %x{$AEL_PATH_BASE64/tech:path()}x%

I wonder if the visibility set to "parent" for the parameter depends on the level of the process where the object is.
I mean this process is not the main process: it's a child process.
So I wonder if "parent" means "the main process" or just the higher level from the position of the object (here: the child process).

Is that clear?

Thank you.

Great! It works.
But I notice an inconvenient with this syntax: I always have to execute the main process, otherwise this syntax won't work, will it?
Can I define a variable that allows me to execute either the main process, or the subprocess without need to change the syntax? It is usefull for the unit tests.

I hope it is my last question on this topic

Ok, I see.
I think I would prefer the scripting solution, because there isn't any object to "maintain".

Thank you again Thomas.